Originally Posted by
Ian Scofield
Like he said above, if you let it run with all the blast gates open, aka with zero resistance, then the impeller will continue to speed up and speed up since there's no force working against it. When that happens, the motor burns up because it's spinning way faster then it's designed.
Conversely, if there's way too much load, IE all the blast gates are closed, you're creating a vacuum because the dust collector is attempting to pull air through your ducting but nothing is moving because there's no new air being pulled into this system. Therefore the dust collector draws more and more current until it trips the breaker.
In a 60 Hz system, as in the United States, the maximum speed of a two pole induction motor is going to be somewhat less than 3600 RPM. The reason is that with 60 Hz (and two poles), the field is rotating at 3600 RPM. In order to function, the armature must rotate less than 3600 RPM. Current is induced in the armature by the wires of the armature cutting the magnetic lines of force from the field. The difference between the rotation of the field and the rotation of the armature is known as "slip".
When the motor is running with a very light load, the armature will rotate faster because less armature current is needed to overcome the resistance of the motor and the load. As the load increases, the slip increases and the armature turns slower. So the "rated" speed of a two pole induction motor in a 60 Hz environment is 3450 RPM, but that is generally only seen at full load. At lighter loads, the speed will be somewhere between 3450 RPM and 3600 RPM (never getting to 3600 RPM).
For the second part of your post, I expect you're assuming that the fan on the motor will overload the motor if it is run "in the open" - without any resistance in the duct work. And when you open sufficient blast gates, it is essentially equivalent to running the motor/fan combination in the open.
Mike
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