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Craig D Peltier
04-10-2008, 8:30 PM
See my rough sketch. I have 2 cat boxes to build and a bench in the middle of this bay window.
Angle is 22.5 degrees. How can I figure out the length of my front , back, top, sides etc.
The dimensions are from back 52.5 wide an its 14" wide x 18 tall.

Whats the easiest way to do this. I do have sketchup but havent learned it yet.
I have a program thats the grandmother of actrix and if I draw a box an then from corner take a line it says the angle but its for example like this 225.14 etc. Im looking for 22.5 right?

I guess I could take a sliding rule and use the 22.5 angle off of that and do a template but there must be an easier program to do this on.

Please help...:confused:

86196

Brian Kerley
04-10-2008, 9:08 PM
Well, I guess I'm not too sure what lengths you need. It'd be fairly easy to do using some trig :cool:. Could you append your sketch to show what dimensions you are wanting to know and I'd be more than happy to help you out.

Eddie Darby
04-10-2008, 9:18 PM
If you want to avoid using math, then make a cut-out with an old cardboard box and some tape, until it looks right to your eye, and then get your measurements.

Craig D Peltier
04-10-2008, 9:28 PM
Well, I guess I'm not too sure what lengths you need. It'd be fairly easy to do using some trig :cool:. Could you append your sketch to show what dimensions you are wanting to know and I'd be more than happy to help you out.

Heres another pdf.

86207

Thanks

Tom Veatch
04-10-2008, 9:40 PM
Heres another pdf.

Thanks

Assuming the included angle in the top right corner is 67.5 degrees (complement of 22.5 degrees), the length of the right side is 14/sin(67.5) = 15.153. The length of the bottom side is 52.5 - 14/tan(67.5) = 46.701.

If the assumed angle is different, just plug the correct angle into the formula in place of the 67.5 value.

Tom Henderson2
04-10-2008, 9:42 PM
HI Craig-

Sorry to work you so hard on this, but you really need to indicate what the angle is on your sketch. I know you mentioned 22.5 degrees in your initial post, but it isn't clear if that is the angle that the bay window makes with the walls, or the acute angle in the second sketch, or what.

The devil is in the details....

-Tom H.

Brian Kerley
04-10-2008, 9:50 PM
Ok, here's the way to do it. I'm assuming that the interior angle at the top right is 67.5 degrees. So, with a length of 14" on the opposite side, that would give you a total hypotenuse length of:

opposite / (sin angle) = hypoteneuse
14/sin 67.5 = 15.153 inches (make sure your calculator is in radians, not degrees)

Then, the other long side will be the following
52.5 - adj = ??

So, the adjacent side of the right triangle is going to be:
opposite / (tan angle) = adjacent
14/tan 67.5 = 5.799 inches

So, the other side is 52.5-5.799 = 46.701 inches

That gives you the right edge a length of 15 5/32 inches and a bottom edge a length of 46 45/64 inches.

What I would do is not worry about it though. Cut a piece of wood with dimensions of 52.5" x 14". Then, on one corner, draw your angle from one side to the other, and cut it off. Then it will be pretty accurate without having to bust out the magnifying glass on your ruler.

Craig D Peltier
04-10-2008, 9:54 PM
HI Craig-

Sorry to work you so hard on this, but you really need to indicate what the angle is on your sketch. I know you mentioned 22.5 degrees in your initial post, but it isn't clear if that is the angle that the bay window makes with the walls, or the acute angle in the second sketch, or what.

The devil is in the details....

-Tom H.

Its a 22.5 degree angle that I want the box end built at. Its the angle of the bay window. So essentailly if I pull all three units away from wall one inch the angle still remains the same I believe.

David DeCristoforo
04-10-2008, 10:21 PM
MATH??? What math? Draw it out full size. Forget the math!

:):):)

Alex Yeilding
04-10-2008, 10:53 PM
opposite / (sin angle) = hypoteneuse
14/sin 67.5 = 15.153 inches (make sure your calculator is in radians, not degrees)

I think you said that backwards. If you want the sine of 67.5 degrees, you need the calculator set to degrees, not radians.

Brian Kerley
04-10-2008, 10:59 PM
Yeah, sorry, meant degrees not radians. Ever tell yourself not to screw something up and you end up doing it regardless? :D

Greg Cuetara
04-10-2008, 11:10 PM
MATH??? What math? Draw it out full size. Forget the math!

:):):)

I Kinda like David's math! :rolleyes:

Gary Muto
04-10-2008, 11:12 PM
Too many unknowns for me. I would need at least one more length or one angle, assuming the other two are 90 degrees.
edit. since I started to reply and delayed my response I see the angle is 22.5 degrees.

Stephen Edwards
04-11-2008, 12:38 AM
MATH??? What math? Draw it out full size. Forget the math!

:):):)

That's my style, too! Forget the math. Just build it to fit and look nice!

Mike Conley
04-11-2008, 11:55 AM
Here is what it looks like when I draw it in AutoCAD.

Craig D Peltier
04-11-2008, 12:28 PM
Here is what it looks like when I draw it in AutoCAD.

Thanks I printed it.I really need to learn sketchup.

Ron Bontz
04-11-2008, 11:59 PM
An engineering instructor once told me that somewhere along the way in your 2nd or third year your brain becomes twisted and everything becomes a mathematical problem. :D Another told me there are always numerous ways to solve the same problem. Indeed, this forum is always an enjoyable learning experience and a reminder of just that.:)

Stephen Edwards
04-12-2008, 8:16 AM
An engineering instructor once told me that somewhere along the way in your 2nd or third year your brain becomes twisted and everything becomes a mathematical problem. :D Another told me there are always numerous ways to solve the same problem. Indeed, this forum is always an enjoyable learning experience and a reminder of just that.:)

I agree with Ron's take on this. There ARE several ways to approach and solve any woodworking problem. Beyond simple math, I'm lost trying to solve things mathmatically. However, with a square, a sliding bevel square and good measuring device and some layout material to work with.......I can get it done.

Will Blick
04-13-2008, 2:44 AM
Stephen, I hear ya.... but sometimes it's better to be assured you have the EXACT answer through math, vs. measuring, which is prone to error, specially when errors are additive.


A simple approach to solving these problems is "Microsoft Math". A $25 download. One of the programs contained inside is called Triangle Solver. I think there might be a few free ones which are web based. Anyway, you simply fill in what you know, and it figures out the rest for you... no reason to remember Trig and Geometry :-)


the reason I suggest this is....most all ww problems can be partitioned down to triangles, which with the help of this software, is now easy to solve. IIRC, of the 6 factors, (3 angles and 3 leg lengths), you need to know any 3 of the variables, the software gives you the other 3.

Tom Veatch
04-13-2008, 3:12 AM
...you need to know any 3 of the variables, the software gives you the other 3.

You need at least one length and then any two of the remaining 5 variables will define the triangle.

Will Blick
04-13-2008, 5:47 PM
Yep, thanks Tom... I got too lose with my description :-)

matt pickston
04-13-2008, 9:46 PM
Hope this is right. Been a while.